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If $\tan \theta + \sec \theta = \sqrt{3}$, then the principal value of $\theta + \frac{\pi}{6}$ is equal to :


( A ) $\frac{\pi}{3}$
( B ) $\frac{3 \pi}{4}$
( C ) $\frac{2\pi}{3}$
( D ) $\frac{\pi}{4}$

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