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If the escape velocity on earth is 11.2 km/sec, its value for a planet having double the radius and 8 times the mass of earth is .............. m/s.

1 Answer

Vp/Ve=underoot of Mp/Me.Rp/Re. Mp=8.Me,Rp=2Re,Vp/11.2=underoot8.Me/Me.Re/2.Re,Vp/11.2=underoot of 4,Vp/11.2=2,Vp=22.4
answered Oct 26 by gsrkomali
 

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