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The energy of the electron in the hydrogen atom is given by the expression:

\[\begin {array} {1 1} (a)\;\frac{-e^2}{r^2} & \quad  (b)\;\frac{-n^2h^2}{2 \pi 2z^2 e^4m} \\  (c)\;\frac{-2\pi^2 z^2e^4}{n^2h^2} & \quad (d)\;\frac{nh}{2 \pi} \end {array}\]

1 Answer

$(c)\;\large\frac{-2\pi^2 z^2e^4}{n^2h^2}$
answered Nov 7, 2013 by pady_1
 
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