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Q)

$y = x^2 \sin 2x$, then $n^{th}$ derivative of $y ( n = 4m)$ is :


( A ) $2^{4m} (x^2 \sin 2x - x \cos 2x - 2m \sin 2x)$
( B ) $2^{4m} (x^2 \sin 2x + x \cos 2x + 2 \sin 2x)$
( C ) $2^{4m} (mx^2 \sin 2x + x \cos 2x + 2m \sin 2x)$
( D ) $2^{4m} (x^2 \sin 2x - 4 m x \cos 2x - m (4m-1) \sin 2x)$

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