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$9.8\;g$ of $H_2 SO_4$ is present in two liters of a solution. The molarity of the solution is :

\[(a)\;0.1\;M \quad (b)\;0.05\;M \quad (c)\;0.2\;M \quad (d)\;0.01\;M\]

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(b) 0.05 M
answered Nov 7, 2013 by pady_1

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