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Questions  >>  CBSE XII  >>  Math  >>  Integrals
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Integrate the function $\frac{\large x^2}{(\large 2+3x^3)^3}$

$\begin{array}{1 1} \frac{-1}{18(2+3x^3)^2}+c. \\ \frac{1}{18(2+3x^3)^3}+c. \\ \frac{-1}{18(2+3x^3)^3}+c. \\ \large \frac{1}{9(2+3x^3)^2}+c.\end{array}$

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