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Questions  >>  CBSE XII  >>  Math  >>  Integrals
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Integrate the function $(x^3-1)^\frac{1}{3}\;x^5$

$\begin{array}{1 1}\frac{1}{7}(x^3-1)^\frac{7}{3}+\frac{1}{4}(x^3-1)^\frac{4}{3}+c \\ \frac{1}{5}(x^3-1)^\frac{5}{3}+\frac{1}{4}(x^3-1)^\frac{4}{3}+c \\ \frac{1}{7}(x^2-1)^\frac{7}{3}+\frac{1}{4}(x^2-1)^\frac{4}{3}+c\\ \frac{1}{5}(x^2-1)^\frac{5}{3}+\frac{1}{4}(x^2-1)^\frac{4}{3}+c\end{array}$

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