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$\tan x-\tan 3x-\tan 2x $ is equal to :

\[(a)\;\tan 8x \; \tan 2x\;\tan x \quad (b)\;\sin 5x \; \sin 3x\;\sin 2x \quad (c)\;\tan 5x \; \tan 3x\;\tan 2x \quad (d)\;\cos 5x \; \cos 3x\;\cos 2x\]

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$(c)\;\tan 5x \; \tan 3x\;\tan 2x$
answered Nov 7, 2013 by pady_1
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