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If the mean and variance of a binomial distribution are $\large\frac{15}{4}$ and $\large\frac{15}{16}$. The number of trials are:

\[(a)\;2 \quad (b)\;4 \quad (c)\;5 \quad (d)\;6\]

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(c) 5
answered Nov 7, 2013 by pady_1

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