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The equation of the circle passing through (2,1) and touching the co-ordinate axes, is :
$(a)\;x^2+y^2-2x-2y+1=0$
$(b)\;x^2+y^2+2x+2y+1=0$
$(c)\;x^2+y^2-2x-2y-1=0$
$(d)\;x^2+y^2+2x-2y-1=0$
jeemain
eamcet
math
1991
q12
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asked
Sep 13, 2013
by
meena.p
edited
Dec 23, 2013
by
meenakshi.p
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1 Answer
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$(a)\;x^2+y^2-2x-2y+1=0$
answered
Nov 7, 2013
by
pady_1
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