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Home  >>  EAMCET  >>  Mathematics
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The equation of the circle passing through (2,1) and touching the co-ordinate axes, is :

$(a)\;x^2+y^2-2x-2y+1=0$

$(b)\;x^2+y^2+2x+2y+1=0$

$(c)\;x^2+y^2-2x-2y-1=0$

$(d)\;x^2+y^2+2x-2y-1=0$
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1 Answer

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$(a)\;x^2+y^2-2x-2y+1=0$
answered Nov 7, 2013 by pady_1
 

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