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Home  >>  EAMCET  >>  Mathematics
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Tha smallest value of $x^2-3x+3$ in the interval $(-3,\large\frac{3}{2})$ is equal to :

\[(a)\;-20 \quad (b)\;-15 \quad (c)\;\frac{3}{4} \quad (d)\;5\]
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1 Answer

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(c) $\large\frac{3}{4}$
answered Nov 7, 2013 by pady_1
 

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