The statement is a contradiction.
$\begin{matrix} p & q & \sim p & \sim q & p \vee (\sim q) & (\sim q)\vee p & (p\wedge(\sim p))\wedge((\sim q)\wedge p) \\ T & T & F& F & F & F & F\\ T & F & F & T & F & T & F\\ F& T & T & F & F & F & F\\ F& F & T & T& F & F & F \end{matrix}$