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Home  >>  EAMCET  >>  Mathematics

$\bigg\{x \in R \bigg | \log \bigg[(1.6)^{1-x^2}-(0.625)^{6(1+x)}\bigg] \in R\bigg\}$=

\[\begin {array} {1 1} (a)\;(- \infty,-1) \cup (7, \infty) & \quad (b)\;(-1,5) \\ (c)\;(1,7) & \quad (d)\;(-1,7) \end {array}\]

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$(d)\;(-1,7)$
answered Nov 7, 2013 by pady_1
 
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