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# 10 men and 6 women are to be seated in a row so that no two women sit together. The number of ways they can be seated is :

$\begin {array} {1 1} (a)\;11!\;10! & \quad (b)\;\frac{11 !}{6!\;5!} \\ (c)\;\frac{10 !\; 9!}{5!} & \quad (d)\;\frac{11 !\; 10 !}{5 !} \end {array}$

Can you answer this question?

$(d)\;\large\frac{11 !\; 10 !}{5 !}$
answered Nov 7, 2013 by