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If $x$ is small so that $x^2$ and higher powers can be neglected, then the approximate value for $\large\frac{(1-2x)^{-1}(1-3x)^{-2}}{(1-4x)^{-3}}$ is :

\[(a)\;1-2x \quad (b)\;1-3x \quad (c)\;1-4x \quad (d)\;1-5x \]
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(c) 1-4x
answered Nov 7, 2013 by pady_1
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