Browse Questions

# If $x$ is small so that $x^2$ and higher powers can be neglected, then the approximate value for $\large\frac{(1-2x)^{-1}(1-3x)^{-2}}{(1-4x)^{-3}}$ is :

$(a)\;1-2x \quad (b)\;1-3x \quad (c)\;1-4x \quad (d)\;1-5x$

(c) 1-4x