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If $\large\frac{1}{x^4+x^2+1}=\frac{Ax+B}{x^2+x+1}+\frac{Cx+D}{x^2-x+1}$, then $C+D=$

\[(a)\;-1 \quad (b)\;1 \quad (c)\;2 \quad (d)\;0 \]

1 Answer

(d) 0
answered Nov 7, 2013 by pady_1
 
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