logo

Ask Questions, Get Answers

X
 
Home  >>  EAMCET  >>  Mathematics

The set of solutions satisfying both $x^2+5x+6 \geq 0$ and $x^2+3x-4 < 0$ is:

\[(a)\;(-4,1) \quad (b)\;(-4,-3]\;\cup\;[-2,1) \quad (c)\;(-4,-3) \; \cup \; (-2,1) \quad (d)\;[-4,-3] \cup [-2,1] \]
Download clay6 mobile app

1 Answer

$(b)\;(-4,-3]\;\cup\;[-2,1)$
answered Nov 7, 2013 by pady_1
 
...