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Home  >>  EAMCET  >>  Mathematics
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The set of solutions satisfying both $x^2+5x+6 \geq 0$ and $x^2+3x-4 < 0$ is:

\[(a)\;(-4,1) \quad (b)\;(-4,-3]\;\cup\;[-2,1) \quad (c)\;(-4,-3) \; \cup \; (-2,1) \quad (d)\;[-4,-3] \cup [-2,1] \]
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$(b)\;(-4,-3]\;\cup\;[-2,1)$
answered Nov 7, 2013 by pady_1
 
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