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Home  >>  EAMCET  >>  Mathematics
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If $A=\begin{bmatrix} -8 & 5 \\ 2 & 4 \end{bmatrix}$ satisfies the equation $x^2+4x-p=0,$ then $p=$

\[(a)\;64 \quad (b)\;42 \quad (c)\;36 \quad (d)\;24\]
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(b) 42
answered Nov 7, 2013 by pady_1
 

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