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$\large\frac{(1+i)x-i}{2+i}+\frac{(1+2i)y+i}{2-i}$$=1=>(x,y)=$

\[\begin {array} {1 1} (a)\;\bigg[\frac{7}{3},\frac{-7}{15}\bigg] & \quad (b)\;\bigg[\frac{7}{3},\frac{7}{15}\bigg] \\ (c)\;\bigg[\frac{7}{5},\frac{-7}{15}\bigg] & \quad (d)\;\bigg[\frac{7}{5},\frac{7}{15}\bigg] \end {array}\]

1 Answer

$(a)\;\bigg[\frac{7}{3},\frac{-7}{15}\bigg]$
answered Nov 7, 2013 by pady_1
 
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