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$\cos ^{-1} \bigg(\large\frac{5}{13}\bigg)$$+\cos ^{-1} \bigg(\large\frac{3}{5}\bigg)$$=\cos ^{-1} x=>x=$

\[(a)\;\frac{3}{65} \quad (b)\;\frac{-36}{65} \quad (c)\;\frac{-33}{65} \quad (d)\;-1\]

1 Answer

$(c)\;\frac{-33}{65}$
answered Nov 7, 2013 by pady_1
 
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