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# If, in $\Delta\; ABC,\large\frac{1}{a+c}+\frac{1}{b+c}=\frac{3}{a+b+c}$ then the angle $C=$

$(a)\;30^{\circ} \quad (b)\;45^{\circ} \quad (c)\;60^{\circ} \quad (d)\;90^{\circ}$

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(c) $60^{\circ}$