Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  EAMCET  >>  Mathematics
0 votes

A person observes the top of a tower from a point A on the ground. The elevation of the tower from this point is $60^{\circ}$. He moves $60\;m$ in the direction perpendicular to the line joining A and base of the tower. The angle of elevation of the tower from this point is $45^{\circ}.$ Then the height of the tower (in meters) is

\[(a)\;60 \sqrt {\frac{3}{2}} \quad (b)\;60 \sqrt{2} \quad (c)\;60 \sqrt{3}\quad (d)\;60 \sqrt {\frac{2}{3}}\]

Can you answer this question?

1 Answer

0 votes
$(a)\;60 \sqrt {\frac{3}{2}}$
answered Nov 7, 2013 by pady_1

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App