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Two fair dice are rolled. The probability of the sum of digits on their faces to be greater that or equal to 10 is
\[(a)\;\frac{1}{5} \quad (b)\;\frac{1}{4} \quad (c)\;\frac{1}{8} \quad (d)\;\frac{1}{6} \]
jeemain
eamcet
math
2013
q38
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Sep 16, 2013
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meena.p
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$(d)\;\frac{1}{6} $
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Nov 7, 2013
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pady_1
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