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Two fair dice are rolled. The probability of the sum of digits on their faces to be greater that or equal to 10 is

\[(a)\;\frac{1}{5} \quad (b)\;\frac{1}{4} \quad (c)\;\frac{1}{8} \quad (d)\;\frac{1}{6} \]
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$(d)\;\frac{1}{6} $
answered Nov 7, 2013 by pady_1

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