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If the equation $ax^2+2hxy+by^2+2gx+2fy+c=0$ represents a pair of straight lines, then the square of the distance of their point of intersection from the origin is

\[(a)\;\frac{c(a+b)-af^2-bg^2}{ab-h^2} \quad (b)\;\frac{c(a+b)+f^2+g^2}{ab-h^2} \quad (c)\;\frac{c(a+b)-f^2-g^2}{ab-h^2} \quad (d)\;\frac{c(a+b)-f^2-g^2}{(ab-h^2)^2} \]
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1 Answer

$(c)\;\frac{c(a+b)-f^2-g^2}{ab-h^2}$
answered Nov 7, 2013 by pady_1
 

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