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$D(2,1,0),E(2,0,0),F(0,1,0)$ are mid-points of the sides $BC,CA,AB$ of $\Delta ABC$ respectively. Then, the centroid of $\Delta ABC$ is

\[(a)\;\bigg[\frac{1}{3},\frac{1}{3},\frac{1}{3}\bigg] \quad (b)\;\bigg[\frac{4}{3},\frac{2}{3},0\bigg] \quad (c)\;\bigg[\frac{-1}{3},\frac{1}{3},\frac{1}{3}\bigg] \quad (d)\;\bigg[\frac{2}{3},\frac{1}{3},\frac{1}{3}\bigg] \]

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