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$\large\frac{d}{dx}$$ [(x+1)(x^2+1)(x^4+1)(x^8+1)]=(15x^p-16x^q+1)(x-1)^{-2}=>(p,q)=$

\[(a)\;(12,11)\quad (b)\;(15,14) \quad (c)\;(16,14) \quad (d)\;(16,15) \]

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A)
(d) (16,15)
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