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$\cos ^{-1} \bigg(\large\frac{y}{b} \bigg)$$=2 \log \bigg(\large\frac{x}{2}\bigg),$$ x > 0=>x^2 \large\frac{d^2y}{dx^2}$$+x \large\frac{dy}{dx}=$

\[(a)\;4y \quad (b)\;-4y \quad (c)\;0 \quad (d)\;-8y \]
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1 Answer

(b) -4y
answered Nov 7, 2013 by pady_1
 
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