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The relation between pressure $p$ and volume $v$ is given by $pv^{\large\frac{1}{4}}$=Constant. If the percentage decrease in volume is $\large\frac{1}{2}$, then the percentage increase in pressure is

\[(a)\;-\frac{1}{8}\quad (b)\;\frac{1}{16} \quad (c)\;\frac{1}{8} \quad (d)\;\frac{1}{2} \]

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1 Answer

(c) $\frac{1}{8}$
answered Nov 7, 2013 by pady_1
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