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If $\int \limits_0^b \large\frac{dx}{1+x^2}$$=\int \limits_b^{\infty} \large \frac{dx}{1+x^2},$ then $b=$

\[(a)\;\tan ^{-1}\bigg(\frac{1}{3}\bigg)\quad (b)\;\frac{\sqrt 3}{2} \quad (c)\;\sqrt 2 \quad (d)\;1 \]

1 Answer

$(d)\;1$
answered Nov 7, 2013 by pady_1
 
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