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The area (in square units) bounded by the curves $x=-2y^2$ and $x=1-3y^2$ is

\[(a)\;\frac{2}{3}\quad (b)\;1 \quad (c)\;\frac{4}{3} \quad (d)\;\frac{5}{3} \]

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1 Answer

$(c)\;\frac{4}{3}$
answered Nov 7, 2013 by pady_1
 
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