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The solution of the differential equation $\large\frac{dy}{dx}$$-2y \tan 2x =e^x\;sec 2x$ is :

\[(a)\;y\;\sin 2x=e^x+c \quad (b)\;y \cos 2x=e^x+c \quad (c)\;y=e^x \cos 2x+c \quad (d)\;y \cos 2x+e^x=c \]

1 Answer

$(b)\;y \cos 2x=e^x+c$
answered Nov 7, 2013 by pady_1
 
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