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The upper half of an inclined plane with an angle of inclination $\phi$, is smooth while the lower half is rough. A body starting from rest at the top of the inclined plane comes to rest at the bottom of the inclined plane. Then the coefficient of friction for the lower half is

\[(a)\;2 \tan \phi \quad (b)\;\tan \phi \quad (c)\;2 \sin \phi \quad (d)\;2 \cos \phi \]

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(a) $2\tan \phi$
answered Nov 7, 2013 by pady_1

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