Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  EAMCET  >>  Physics
0 votes

A uniform circular disc of radius R, lying on a friction less horizontal plane is rotating with an angular velocity $\omega$ about its own axis. Another identical circular disc is gently placed on the top of the first disc coaxially. The loss in rotational kinetic energy due to friction between the two discs, as they acquire common angular velocity is (I is moment of inertia of the disc)

\[(a)\;\frac{1}{8} I \omega \quad (b)\;\frac{1}{4} I \omega^2 \quad (c)\;\frac{1}{2}I \omega ^2 \quad (d)\;I \omega ^2 \]
Can you answer this question?

1 Answer

0 votes
$(b)\;\frac{1}{4} I \omega^2 $
answered Nov 7, 2013 by pady_1

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App