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Two particles A and B of masses 'm' and '2m' are suspended from two mass less springs of force constants $K_1$ and $K_2$. During their oscillation, if their maximum velocities are equal, then ratio of amplitudes of A and B is

\[(a)\;\frac{K_1}{K_2} \quad (b)\;\frac{K_2}{2K_1} \quad (c)\;\frac{K_2}{K_1} \quad (d)\;\frac{2 K_1}{K_2} \]

1 Answer

$(b)\;\frac{K_2}{2K_1}$
answered Nov 7, 2013 by pady_1
 

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