logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
Home  >>  EAMCET  >>  Physics
0 votes

Two particles A and B of masses 'm' and '2m' are suspended from two mass less springs of force constants $K_1$ and $K_2$. During their oscillation, if their maximum velocities are equal, then ratio of amplitudes of A and B is

\[(a)\;\frac{K_1}{K_2} \quad (b)\;\frac{K_2}{2K_1} \quad (c)\;\frac{K_2}{K_1} \quad (d)\;\frac{2 K_1}{K_2} \]

Can you answer this question?
 
 

1 Answer

0 votes
$(b)\;\frac{K_2}{2K_1}$
answered Nov 7, 2013 by pady_1
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...