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# A capillary tube of radius 'r' is immersed in water rises to a height of 'h'. Mass of water in the capillary tube is $5 \times 10^{-3}\;kg$. The same capillary tube is now immersed in a liquid whose surface tension is $\sqrt 2$ times the surface tension of water. The angle of contact between the capillary tube and this liquid is $45^{\circ}$. The mass of liquid which rises into the capillary tube now is , (in kg)

$(a)\;5 \times 10^{-3}\quad (b)\;2.5 \times 10^{-3} \quad (c)\;5 \sqrt 2 \times 10^{-3} \quad (d)\;3.5 \times 10^{-3}$
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## 1 Answer

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$(a)\;5 \times 10^{-3}$
answered Nov 7, 2013 by

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