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The sensitivity of a galvanometer that measures current is decreased by $\large\frac{1}{40}$ times by using shunt resistance of $10 \;\Omega$. Then, the value of the resistance of the galvanometer is

\[(a)\;400\; \Omega \quad (b)\;410\; \Omega \quad (c)\;30\;\Omega \quad (d)\;390\;\Omega \]

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(a) $390\; \Omega$
answered Nov 7, 2013 by pady_1

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