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The work function of a metal is $2$ eV. If a radiation of wavelength 3000 A is incident on it, the maximum kinetic energy of the emitted photo electrons is

\[(a)\;4.4 \times 10^{-19}\;J \quad (b)\;5.6 \times 10^{-19}\;J \quad (c)\;3.4 \times 10^{-9}\;J \quad (d)\;2.5 \times 10^{-19}\;J\]

1 Answer

$(c)\;3.4 \times 10^{-9}\;J$
answered Nov 7, 2013 by pady_1

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