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The radius of $_{72}Te^{125}$ nucleus is $6$ fermi . The radius of $_{13}AI^{27}$ nucleus in meters is

\[(a)\;3.6 \times 10^{-12} \;m \quad (b)\;3.6 \times 10^{-15}\;m \quad (c)\;7.2 \times 10^{-8}\;m \quad (d)\;7.2 \times 10^{-15}\;m\]

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$(b)\;3.6 \times 10^{-15}\;m$
answered Nov 7, 2013 by pady_1

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