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# Diborane reacts with HCl in the presence of $AlCl_3$ and liberates:

$(a)\;H_2 \quad (b)\;Cl_2 \quad (c)\;BCl_3 \quad (d)\;Cl_2\; \&\; BCl_3$

Can you answer this question?

$(a)\;H_2$
answered Nov 7, 2013 by