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Q)

How much AgCl will be formed by adding 200 ml of 5 M HCl to the solution containing 1.7 gms of $Ag NO_3$?

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A)
Solution :
$AgNO_3+HCl \to AgCl+HNO_3$
200 ml of 5M HCl contains 1.7 g of $AgNO_3$
$\qquad= \large\frac{1.7 \times 1000}{200 \times 5}$$=1.7\;g$
Hence 1 M Solution of HCl contains $1.7 \;g\;of\;AgNO_3$
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