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Q)

The molarity of con. HCl is 1.15 M; What volume of con. HCl is required to make 1.00 of $0.1\;M\;HCl$

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A)
Solution :
$V_1M_1=V_2M_2$
$1000 ml \times 0.1 \;M =V_2 \times 1.15\;M$
$V_2=\large\frac{1000 \times 0.1}{1.15}$$\;ml$
$\qquad= 86.9\;ml$
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