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Home  >>  EAMCET  >>  Mathematics
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$\lim\limits_{x \to 8} \large\frac{\sqrt {1+\sqrt {1+x}}-2}{x-8}=$

\[(a)\;\frac{3}{2} \quad (b)\;\frac{1}{4} \quad (c)\;\frac{1}{24} \quad (d)\;0\]
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$(c) \frac{1}{24}$
answered Nov 7, 2013 by pady_1
 
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