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Q)

If the concentration of glucose $(C_6H_{12}O_6)$ in blood is $0.9\;g\;L^{-1}$. What will be the molarity of glugose in blood ?

$\begin{array}{1 1} (a)0.005\;M \\ (b)0.008\;M\\ (c) 0.07\;M\\ (d) 0.09\;M \end{array} $

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A)
Solution :
Molar mass of glucose $(C_6H_{12}O_6)$
$\qquad= 12 \times 6 +1 \times 12 +16 \times 6=180$
Molarity $= \large\frac{conc. in\;gL^{-1}}{Molar\;Mass}$
$\qquad= \large\frac{0.90\;gL^{-1}}{180\;g\;mol^{-1}}$$=0.005\;M$
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