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If $f(x) =|x|+ | \sin x|$ for $x \in \bigg(-\large\frac{\pi}{2},\frac{\pi}{2}\bigg),$ then its left hand derivative at $x=0$ is

\[(a)\;0 \quad (b)\;-1 \quad (c)\;-2 \quad (d)\;-3\]

1 Answer

(c) -2
answered Nov 7, 2013 by pady_1
 

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