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Questions  >>  EAMCET  >>  Mathematics
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If $1^{\circ}=\alpha$ radians then the approximate value of $\cos(60^{\circ}1')$ is

\[(a)\;\frac{1}{2}+\frac{\alpha \sqrt 3}{120} \quad (b)\;\frac{1}{2}-\frac{\alpha}{120} \quad (c)\;\frac{1}{2}-\frac{\alpha \sqrt 3}{120} \quad (d)\;\frac{1}{2}+\frac{\alpha}{120}\]

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