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$u=u(x,y)=\sin (y+ax)-(y+ax)^2=>$

\[(a)\;u_{xx}=a^2.u_{yy} \quad (b)\;u_{yy}=a^2u_{xx} \quad (c)\;u_{xx}=-a^2.u_{yy} \quad (d)\;u_{yy}=-a^2u_{xx}\]

1 Answer

$(a)\;u_{xx}=a^2.u_{yy}$
answered Nov 7, 2013 by pady_1
 

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