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$\int \large\frac{1+\cos 4x}{\cot x -\tan x}$$dx$=

\[\begin {array} {1 1} (a)\;-\frac{1}{4} \cos 4x+c & \quad (b)\;\frac{1}{8} \cos 4x+c \\ (c)\;\frac{1}{4} \sin 4x+c & \quad (d)\;-\frac{1}{8} \cos 4x+c \end {array}\]

1 Answer

$(d)\;-\frac{1}{8} \cos 4x+c $
answered Nov 7, 2013 by pady_1
 
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