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The area (in square units) of the region bounded by the curves $x=y^2$ and $x=3-2y^2$ is

\[\begin {array} {1 1} (a)\;\frac{3}{2} & \quad (b)\;2 \\ (c)\;3 & \quad (d)\;4 \end {array}\]
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1 Answer

$ (d)\;4 $
answered Nov 7, 2013 by pady_1
 

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