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If $a,b$ and $n$ are natural numbers then $a^{n-1}+b^{n-1}$ is divisible by:

\[\begin {array} {1 1} (a)\;a+b & \quad (b)\;a-b \\ (c)\;a^3+b^3 & \quad (d)\;a^2+b^2\end {array}\]
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1 Answer

$(a)\;a+b$
answered Nov 7, 2013 by pady_1
 
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