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A bag contains $n$ white and $n$ black balls. Pairs of balls are drawn at random without replacement successively, until the bag is empty. If the number of ways in which each pair consists of one white and one black balls is $14,400.$ then $n=$
\[\begin {array} {1 1} (a)\;6 & \quad (b)\;5 \\ (c)\;4 & \quad (d)\;3 \end {array}\]
jeemain
eamcet
math
2011
q22
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Sep 20, 2013
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meena.p
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Nov 7, 2013
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